SOAL TRIGONOMETRI
(MATEMATIKA KELAS X SMA /MA /SMK /MAK)
Oleh : Suryadi
Direction of Education Apenso Indonesia
Soal:
Jika sin α = - 1/5 dan π < α < 3/2 π, maka ( cos α + tan α )/ 2 = .......
Penyelesaian:
Lihat gambar di atas
r² = y² + x²
5² = 1² + x²
x² = 5² - 1²
x² = 25 – 1
x² = 24
x = √24 = 2 √6
sin α = - y / r = - 1 / 5 ....( kwadran III )
cos α = - x / r = - 2 √6 / 5 ( kwadran III )
tan α = sin α / cos α
= ( - 1/5 ) / ( - 2√6/5 )
= ( - 1/5 ) x ( 5/( - 2√6 ))
= 1/2√6
= 1/2√6 x √6/√6
= √6/12
( Cos α + tan α ) / 2 = { (2√6/5) + √6/12 } / 2
= ( - 2√6 )/10 + √6/24
= ( - 24√6 )/120 + ( 5√6 )/120
= - 19√6 / 120
Hubungi : WA 0823 3846 4171
🌸Selamat Belajar & Good Luck!🌸
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